Are we gonna be able to upload replays from the 0.6B version to lfsworld after the new patch is released?

Full Name: Paweł Kulijewicz
Team: Last Lap Motorsports
Number: 66

Yeah, LFSW sometimes is working fine, sometimes not at all - no matter what I click, it doesn't work, I have to reload the site.

!

I have uploaded a hotlap today (SO4 FZ5) and I'm unable to open it in the hotlap analyzer (first time someting like this happens to me).

"Unable to load RAF file pajkul_SO4_FZ5_147100.raf"

Actually it happened to me a few times, but the solution was simple - i just tried again and it worked. This time it doesn't work even after 10 mins. I deleted the hotlap, uploaded it again - nothing. The .spr file is corrupted or what?

Thanks for help.

edit: Sorry, didn't check. Of course it's a temporary problem with LFSW, cause nobody's lap is converted into raf file.

Last edited by pajkul, Fri, 22 Jun 2012 11:36.

Do you want good physics or good AI? Because as far as the current CPUs are concerned, there's no way we could get both at the same time.

LOL. Period.

Take it easy.

Quote from DarknessPainF1 :

http://www.troll.me/images/futurama-fry/yes-yes-indeed.jpg

Master Race Car vs. My3id vs. spdo vs. WW vs. SR vs. GENR vs. CoRe...

Yes, LOL.

Last edited by pajkul, Wed, 16 May 2012 14:21.

Ok, but the rules were stated in the first post and no matter how much you like to socialize, you don't match the criteria.

Quote from frotto110 :

few posts up

But if you look carefully, you can see that your stats show you have travelled 0 kilometers in LFS, completed 0 laps in LFS, burned 0 liters of fuel in LFS, joined 0 hosts in LFS, completed 0 races in LFS which is not that impressive, especially for a person wanting a reward of S1/S2 license for it.

Ask CheerioDM

Maybe for you.

No force-feedback improvements? I think the force feedback effects are DIRECTLY connected with the tyre physics, as everything the driver feels through the steering wheel results from the tyre forces.

LFS devs assume that no matter how long it will take to finish the new updates, we will love the new LFS so much that we'll forget about that waiting and forgive them immediately.
They are probably right, but I'd rather be kept informed about what's going on and how much waiting is left there.

We will get Big Nothing for Christmas
No report, no test patch... nothing as always.

Pawel Kulijewicz (pajkul) - team: none - POL

Name(FIRST+LAST) : Pawel Kulijewicz
Number: 58
LFSUsername: pajkul
Team: [SIW]
Country: Poland

Name: P.Kulijewicz
LFSF name: pajkul
Team: [SIW]
Car: FZR
Number: 73

I'm not sure if this bug has been adressed already.

So the thing is when in the hotlap mode a replay is played in slow motion, after pressing shift+R the restart takes too much time, the process is slowed down too. That's annoying.

Offtop: Where can I find the description of the forces displayed after pressing F button?

Last edited by pajkul, Wed, 15 Jun 2011 15:52.

So even if there is the skidmark made by the front left tyre, it doesn't mean the tyre doesn't have grip?

What I meant is when car is turning, the tyres have certain slip angle. If I was taking a turn of the same radius at the same speed, but with a 2 times higher load on the tyres (assuming that there's still enough lateral force, or friction for tyres that they can have grip) would the slip angles increase also 2 times? Assuming that there's no weight transfer from left to right or vice versa to make things more simple.

With regard to your last words, there's such a thing called trail braking.

http://soliton.ae.gatech.edu/p ... tsiotra/Papers/ecc07a.pdf

As it was described here, the techniqe basically consists in moving the weight to the front tyres and thus increasing their grip through the balanced use of brakes and throttle.

As the vehicle decelerates, the weight of the vehicle
transfers from the rear to the front axle and thus, the front
tires generate higher friction than the rear ones.

So it actually generates more oversteer. Or maybe I misunderstood you and what you said is more like braking and accelerating while cornering is basically totally different from the pure weight distribution of a static car. Then yes, I want to discuss that too.

Oh, and probably the most importantly: would you be so kind and explain why the front left tyre is losing grip at TURN 1 during the hotlap, not the front right? The natural thing would be that there's more load on the front left tyre, so it has MORE grip than the front right. Probably this is somehow connected to what you've described before - the higher the vertical load, the lower the friction coefficient. But I can't be sure.
Replay:
http://www.lfsworld.net/get_spr.php?file=72052

P.S. And what is the relation between the steering input I apply and slip angle? Linear, non-linear? I guess up to the point linear, then when at the limit of adhesion, the slip angle is increasing much faster than the steering input.
P.S.2: I've heard many times that this is impossible to maintain a constant rotational speed of a understeery car at constant speed. So this is probably correct for high speeds and when on the limit of adhesion.
P.S.3: So the slip angle decreasing you've described when cornering is caused by the self-aligning torque, right? The lateral force is trying to reduce the slip angle. I forgot about that.

Last edited by pajkul, Sun, 12 Jun 2011 08:37.

Wow, thanks. But my last question remains unanswered: does current slip angle increases linearly with the vertical load on the tyre?

And: why is it that the rear yaw torque decreases to the value of the front tyres?

And no. 2: Is the max. lateral force the maximum friction the contact patch can generate?

Quote from jtw62074 :

63.5/37.5 car:



yaw torque front = 1125* 3 = 3375 lb/ft

yaw torque rear = 825 * 5 = -4125 lb/ft



The last car is unbalanced. In reality what would happen is the rear slip angles would decrease so that the rear yaw torque was -3375 which would balance out the front yaw torque. How much lateral force would be required to get -3375 lb/ft torque at the rear?



yaw torque rear = lateral force * 5 = -3375lb/ft



lateral force at rear to stabilize the car = -3375 / 5 = 675 lb



What's happening here with a real car driving in a circle is that the rear tire force drops down to 675 lb through a reduction in the rear slip angle. It can still make 825 lb if you flick the car hard into the turn momentarily, but once the car settles into the turn the rear will produce 675 lb instead of the maximum 825 lb.

Last edited by pajkul, Fri, 10 Jun 2011 10:04.

Last question, are vertical load on a tyre and the current slip angle linear?

Last edited by pajkul, Thu, 9 Jun 2011 21:55.

Quote from Bob Smith :

Essentially, yes. The net result is that the front tyres need to slip more to create the same (in this case, lateral) force as the rears, which is the definition of understeer.

So if we increase the load on the front tyres X times, the cornering stiffness (and thus the maximum friction the tyres can generate) is increased Y times when (Y<X), assuming that there's no weight transfer from left to right or vice versa during the turn?