no it doesn't work like that, lets do an example:
we have a car with the following parameters.
mass = 1000Kg
max acceleration force = 3000N ( assume constant power simpler calc's )
CdA = 6.24 (
http://en.wikipedia.org/wiki/Automobile_drag_coefficient )
p = 1.204 (
http://en.wikipedia.org/wiki/Density_of_air )
total acceleration force:
Fa = 4000
Fd = 0.5*1.204*6.24*v^2
at max speed:
Fa = Fd
therefore
2.2369 * sqrt( 4000 / ( 0.5*1.204*6.24 ) ) = v ( in MPH )
v = 73 mph
now the load on the tyres:
N = (1000*9.81) / 4 ( assuming even weight distro )
the tyre load is independent of speed, if there was downforce involved there would be a v term in the load equation.
maximum force available to the tyre
u = 0.035 ( coefficient of roll resistance
http://en.wikipedia.org/wiki/Rolling_resistance )
F= uN = ( 0.035 * 1000 * 9.81 ) / 4
as the weight of the car does not change the value of F stays the same and therefore the same maximum grip available from the tyre, but if the car had downforce the weight would increase as the car gets faster and the maximum grip would increase at speed.
So the maximum grip and therefore braking capabilities do not change with speed.
{ hope i did that correct }